
The graphic below is courtesy of [http://www.fueleconomy.gov/feg/atv.shtml]. Go to that page for detailed info on all of the losses.
Free MPG form for tabulating your car's Miles Per Gallon. www.neprimer.com/ePress/articles/2007/MPG.pdf
This calculation is only a "What if"
because the chart does not show the actual Work Out as a percentage.
It only shows the "losses".
Assuming the "TOTAL Work
Output" = 5.8 % , then let's assume that that equals 20 MPG
and that 1 gallon of gas costs $3/Gal. and
where Gasoline: US gallon = HHV = 125,000 Btu/gallon [HHV =
Higher Heating Value.].
[ 20 MPG out / 5.8 %
out = 3.448 mpg / 1.0 % .
And 1.0% of $3 = $0.03 . In other words: 1.0% =
3.448 mpg
and = $0.03]
Then filling in the table from left to
right:
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Again, this says that a gallon of gas in a "20 mpg" car typically expends 94.2% or 324.8 mpg and $2.82 of $3.00/gal. to "losses".
If the 1000° F exhaust gases were used for auxiliary steam engine propulsion with the same losses, what would be the resulting MPG?
- This also says that regenerative attachments are barely going to compensate for their complexity and added maintenance.
- This also says that hybrid attachments are barely going to compensate for their complexity and added maintenance.
- This also says that electric vehicles would only shift the chemical fuel energy transition losses to the power company and add power transmission losses to the total. The car above uses raw chemical fuel energy and transforms it into mechanical motion. The power company would take raw chemical fuel energy transform it into mechanical motion (with losses) to generate electricity to store in a car's batteries (with losses) and the electric car would change the stored electricity into mechanical motion (with losses).
- The most economical use of raw fuel energy resources with the least amount wasted losses is to change it once from chemical fuel energy to mechanical motion.
- The most economical use of the raw fuel energy resources due to Engine LOSSES (78 BTU) is to capture it and convert it into mechanical motion.
CH4 + 2 O2 → 2 H2O + CO2 Water is a waste product."
"Spontaneous chemical processes do not create energy, they release it by converting unstable bonds into more stable bonds and/or by increasing entropy. Water is such an abundant chemical compound in part because it has very stable bonds that resist most reactions. In order for water to participate in a reaction that produces energy, high energy compounds must be added to carry the current and make H2O bonds easier to break. For example, it is possible to generate the combustible fuel hydrogen by adding sodium bicarbonate [NaHCO3.] to water. See [3.] below.
[2.]
"As already noted, water,
particularly when ions are added (salt water or acidic water) can be electrolyzed
(subject to electrolysis). When driven by an external source of
voltage, H+ ions flow to the cathode to combine with electrons to
produce hydrogen gas in a reduction reaction. Likewise, OH- ions flow
to the anode to release electrons and an H+ ion to produce oxygen gas
in an oxidation reaction.
In molten sodium
chloride, when a
current is passed through
the salt
the anode oxidizes chlorine ions (Cl-), which release electrons to the
anode. Likewise the cathode reduces sodium metal (Na+), which accept
electrons from the cathode and deposits on the cathode as sodium metal.
valence shell.
Table Salt as the catalyst. \/
NaCl dissolved in water can also be
electrolyzed. The anode
oxidixes chlorine ions (Cl-), and Cl2
gas is still produced. However, instead of sodium metal, aqueous sodium
hydroxide (NaOH) is produced, which stays dissolved in the water. Some
of the water will also be electrolyzed, producing H2
gas. The oxygen is found in the hydroxide ion which
combines with the
sodium ions to make the sodium hydroxide.
The
net equation is: 2 H2O (l) + 2 NaCl
(aq) --> Cl2(g/aq) + 2 NaOH (aq) + H2
(g)" [http://en.wikipedia.org/wiki/Electrolytic_cell
]
(l) = liquid ;
(aq) = aquious ? ; (g/aq) = gas/aq? ; (g) = gas

Finding
The 100 MPG Carburetor Or What is 100%
MPG? The answer is
dependent upon the power conversion efficiency of your vehicle and your
driving habits.
~
Designed - © 12/22/07 ; 8 Kb .
.
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